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get_n_reverse

async def get_n_reverse(name: str, *, start: int = 0, count: int = None) -> list:

Returns count number of items, beginning from start position, iterating from tail to head.

This is the same as get_n() butstart is relative to the tail: i.e. start = 0 is the tail.

  • count

    • None will get to and including the head
    • Cannot be negative

  • start cannot be negative

Examples

await lst.create('chars', type='str')
await lst.add('chars', ['A', 'B', 'C', 'D', 'E'])

print(await lst.get_n_reverse('chars'))           
print(await lst.get_n_reverse('chars', start=3))  
print(await lst.get_n_reverse('chars', start=1, count=2)) 
print(await lst.get_n_reverse('chars', count=3))
Output
['E', 'D', 'C', 'B', 'A']
['B', 'A']
['D', 'C']
['E', 'D', 'C']